if a number of little droplets of  a liq of density   surface tension t  and specific heat c each of radius r coalesce to form  a droplet of radius R the rise in temperature is ???

come on someone reply

Let n be the number of drops...Then their total surface area is  4nr2.  And their total  volume  will 4/3*nr3. The volume of the larger drop will also be the same...if its radius is R, we have.

4/3R3=n4/3r3. -->  R³=nr³ 

The energy released by the decrease in the total surface area causes the rise in temperature.

Energy(E)=surface tension *decrease in area=t*(4nr² -4R² )

Rise in temp=E/(4/3R³ *c)

Pls rate if satisfactory...

Cheerio