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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: UNITS & DIMENSIONS
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firebolt (0)

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Can any of you please help me with the following problem?
 
The period of oscillation of a simple pendulum turns out to be 2.63 s, 2.56s, 2.42s, 2.71s, and 2.80s. Find :
a) True period of oscillation
b) Absolute error in each measurement
c) Mean absolute error
d) Fractional error
e) percentage error
f) Period of pendulum without error limits
    
chimanshu_007 (11437)

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hii
 
fr this u have to find mean value of the time period first
 = 2.63 + 2.56 + 2.42 + 2.71 + 2.80 / 5 = 2.624
 
2) Absolute error....
taking 2.624 as the true value of the tym period...
 
#T1 = 2.62 - 2.63 = - 0.01
 
#T2 = 2.62 - 2.56 = 0.06
 
#T3 = 2.42 - 2.62 = 0.20
 
#T4 = 2.62 - 2.71 = -0.09
 
#T5 = 2.62 - 2.80 = - 0.18
 
so
 
#T = -0.01 + 0.06 + 0.20 - 0.09 - 0.18 / 5 = -0.02/5 = -0.004
 
Fractional error = #T / T = - 0.004 / 2.62 = 0.0015
 
 
%age error = -0.0015 x 100 = 0.15%

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