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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 00:56:32 IST
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how to find dimension of any new quantity which is not fundamental?i am just starting woth jee preparation..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 01:14:52 IST
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hi, just change all the derived quantities{i.e other than fundamental quantities} into fundamental quantities,and then apply the dimensions and simplify to get the dimension of the required quantity.......... is this wat u wanted or any thing else?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 09:48:46 IST
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Karthik is right as far as your query is concernerd.
For better understanding u can post some unsolved problem on units and dimensions.
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The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 09:54:40 IST
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I will explain with the help of an example.
Force of attraction between two bodies is given by :
F = Gm1m2/r2 , to fond the dimension of G.
G = Fr2/m1m2
As force is (mass)x(acceleration0 its dimension is [M][a] = (M)(LT-2)
[G] = [Fr2/m1m2] = [F][r2]/[m1][m2]
[G] = (MLT--2)(L2)/{(M)(M)}
[G] = M-1L3T-2
Write down the dimensions of the quantities in terms of base quantities and simply do multiplication and division of them.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 10:16:38 IST
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Sir, while finding the pitch of a Scre Gauge.............what if we stated exactly from zero on the Main Scale and after fve rtations......the Main Scale reads 5.4mm or smthng like that............
then is the pitch 1mm or [5.4/5] mm..................Please reply....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 20:56:25 IST
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Hey, Jaysun.. It's (5.4 / 5)mm as : pitch = distance moved / no. of rotations given.. And.. Soumi, For all those quantities which are not fundamental, directly or indirectly they will have a relation with those fundamentals qts. Eg : Velocity = Displacement / Time = [L] / [T] And like this, all those simple quantities may be dimensionalised from which we can find those quantities like 'G' as our Bipin Sir has done...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 21:01:20 IST
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if u r an inter 1st yr student id suggest u refer some gud book or else the inter 1st year text book there a quite a few examples & jst work them out then ull find how simple they are
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Apr 2007 21:12:17 IST
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hello.. can anbody help me out for the problems on optics????? plz reply its urgent...
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--@nkush..... |
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