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maheshnanda_sharukhnadal (0)

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resultant of 2forces P+Q,P-Q is[ ](P2+3Q2).find the angle between 2 forces

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LAMPARD (1142)

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120..Use the fact that resultant of F1 and F2 is root(F12+F22+2F1F2cosx) where x is the angle between the forces.If u want soln,i'l post it.But u better try it first using the idea.

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I tried with that even before but i could come only up to
3P2-Q2=2Q2cosx

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LAMPARD (1142)

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P2+3Q2=2(P2+Q2)+2(P2-Q2)cosx
P2-Q2 +2(P2-Q2)cosx=0
Thus,(P2-Q2)(1+2cosx)=0
Thus,cosx=-0.5
Thus,x=120

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