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maheshnanda_sharukhnadal (0)

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(a)2 forces of magnitudes 3P, 2P have a resultant R.if the first is doubled without changing the angle,the magnitude of resultsnt is doubled. find the angle between the forces.
(b)If the 1st force is tripled what will happen to the resultant

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coolvignesh (1436)

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let the angle b/w the forces be @
therefore, R^2 = 13P^2 + 12P^2 cos@
if 3p bcums 6p
then r = 2r
i.e 4R^2 = 40P^2 + 24P^2cos@

dividing the above two eq
we get
40 + 24cos@ = 52 + 48cos@
10 + 6 cos@ = 13 + 12cos@
6cos@ = -3
cos@ = -0.5
@ = 120 degrees

if first force is tripled....
then resultant becums sq.root of [67/7] times

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