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maheshnanda_sharukhnadal (0)

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the resultant of 2 forces P,Qis equal to P in magnitude and that of 2 forces 2Pand Q act same angle is also P.find Q in terms of  P and angle

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LAMPARD (1142)

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P2 +Q2 +2PQcosx=P2
Thus,Q=-2Pcosx
Using 2nd condition,
3P2+Q2+4PQcosx=0.
Subst. Q in terms of P in this eqn. You get cosx=+ or -root(3)/2
Thus,x=30 or 150.

MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD...
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can oyu also find Q in terms of P

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LAMPARD (1142)

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We know Q= -2Pcosx
Subst. cosx= 3 /2
U get Q=  3 P

MaNuTd RoXxXx..MaNuTd 2 WiN PrEmIeR LeAgUe ThIs SeAsOn ToO AlOnG WiTh ChAmPiOnS LeAgUe.....HaiL RoNaLdO ...HaiL LaMpArD...
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