IIT JEE , AIEEE Forum - Physics , General - very hard-please try

scorpion

A car is driven eastward for a distance of 50km, then northward for 30km, then in a direction 30^o east of north for 25km. Determine the total displacement of the car from its starting point?

spideyunlimited

root of [ (62.5)^2 + ( 30 + 12.5 root3 ) ^2 ]

( i found total displacement along x axis and total displacement along y axis therefore magnintude of displacement is root of x sq + y sq.

scorpion

BUT THE ANSWER GIVEN IN MY BOOK IS

[(62.5)² + (51.65)²] km.

seriousstone89

The answer should be 81.08 km

waterdemon

See its simple ,

The total displacement aong X axis

= 50 + 25Cos60

= 50 + 25*1/2

= 50 + 12.5

= 62.5 m.

Total Displacement along Yaxis

= 30 + 25Sin60

= 30 + 25*3/2

= 30 + 12.5*1.73

= 30 + 21.65

= 51.65 m.

Threrefore the total displacement from original position

=(62.5)²+(51.65)²

=3906.25 + 2667.7225

=6573.9725

=81.08m.

Therefore the total displacement is "81.08m"

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deepak_agarwal

Hey d soln givn above is absolutely correct,,, i hop u hav ndrstood it!!!

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