Mass of earth is =Me = 5.98 x 1024 kg
Due to this mass there is a gravitational force of attraction between earth and objects on the earth.
So, acceleration due to gravity on earth's surface is defined as g = GMe / R2
Where, R is radius of earth ~ 6400km = 6.4 x 106 m
or, g = GMe / R2 = 9.8 m/s2
Now keeping the same fact in mind if we try to asscociate weight of earth it meas
Weight of earth = mass of earth x g'
where g' is accleleration on earth due to bodies present in its vicinity as well due to other celestial bodies like sun etc.
But the bodies on earth are having masses too small that contributes negligibly towards g'
Similarly if we try to find out the contribution from SUN towards g' then
we see that g' = G (mass of sun)/ (distance between sun and earth)2
= G Ms / Res2
Here Res = distance b/w earth and sun = 1.52 x 1011 (Aphelion)
also Res = 1.47 x 1011 ( At the time of Perihelion)
Thus if we take Res = distance b/w earth and sun = 1.52 x 1011
G = 6.64 x 10-11
Ms = 1.98 x 1030 kg
then we find that g' ~ 10-9
Which is far less and negligible.
Weight of earth due to sun = Me x g' ~ 12 x 1015 N
thus in this way the weight of earth can be associated and corelated due to the prescence of celestial or other heavy bodies in its vicinity.
Though there is no specific and standard idea to estimate weight of the earth due to ambiguity involved in the preoblem as evident from above analytical but crude example.