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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Sep 2007 14:17:49 IST
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PLS SOLVE
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Sep 2007 14:37:52 IST
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The answer is that the two images will be formed 50 cm from the pole of the two mirrors on the same side of the object. the distance betn the two images is 3 cm. as the object is placed on the centre of curvature of the mirros the image will be formed on itself. now aply
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Sep 2007 07:35:18 IST
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the crct ans giveen is 50 cm from the 2 miroors, and the distancew between the two images is 2 cm
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B.Tech CSE, ISMU |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Sep 2007 11:49:22 IST
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Aniket your answer is partly wrong and Kislays answer is correct. See distance of image is 50 cm and that can be calculated from mirror formulae.
as far as position of image is concerned. Object is 0.5 cm below optical axis of top half so image will be 0.5 cm above its optial axis. Similarly object is 0.5 cm above optical axis of top half so image will be 0.5 cm below its optial axis. The seperation between two optical axises is 1 cm. So seperation between images is 2 cm
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Sep 2007 09:18:36 IST
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thnx sir 4 the soln
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B.Tech CSE, ISMU |
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