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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Jul 2007 23:09:21 IST
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a thin rodof length d/3 is placed along the pricipal axis of a concave mirrorof focal length=d such that its image, which is real and elongated, just touches the rod. find the length of the image
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solution:::
in a concave mirror we need to take to concepts into consideration:::
i>in case of a concave mirror the image is formed on the object only when then the object is placed at radius of curvature.
ii>the image is magnified and real and inverted only when object is placed between C and F and at F.
here,the farther end is at 2d and near end is at 2d-d/3=5d/3.
the image of farther end is at 2d itself.............(refer to point (i))
and applying mirror formula get the position of near end,we get the position of image to be 5d/2 on same side as that of the object.
thus,image length=5d/2-2d=d/2
THUS,THE LENGTH OF THE IMAGE OF THE ROD IS 0.5d OR d/2.
PLEASE RATE ME....
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28 Jul 2007 01:02:25 IST
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Perfect answer bumba
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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