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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Sep 2008 19:41:48 IST
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A ray of light travel from an optically denser to rarer medium..the critical angle for two media is c.
find the maximum possible deviation ?
explain your answer
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i think the max. possible deviation is (90-c).
when i=c
r=90
the angle formed bet ween initial direction of incident ray and normal is c.
r=90
dev.=r-i(when rays goes from denser to rarer medium.
there fore max. dev = 90-c
if satisfied don t forget to rate
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5 Sep 2008 20:08:10 IST
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your answer is wrong but i agree with your soln
can you tell me how dev=r-i
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5 Sep 2008 20:17:05 IST
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IS the ans very nearly equal to 180 ???
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5 Sep 2008 20:17:41 IST
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deviation means the angle between the refracted ray and the initial direction of the incident ray.
so when a light ray travels from denser to rarer medium it bends away from normal. consequently r>i.
thereforen deviation = (r-i)
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5 Sep 2008 20:20:48 IST
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anay_pat can u pls explain how max. deviation can be 180
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5 Sep 2008 20:21:52 IST
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Can't deviation refer to the angle between incident and reflected ray (in this case)
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5 Sep 2008 20:23:36 IST
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but can u pls show ur working
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5 Sep 2008 20:24:03 IST
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kushi12 can u post the right answer pls
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5 Sep 2008 20:24:14 IST
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Suppose the light ray strikes the interface at about 89.999...... degree .The the angle of reflection will be 89.9999..... Thus angle of deviation is 2(89.999...) which tends to be 180
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5 Sep 2008 20:24:51 IST
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Is my ans correct ????
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5 Sep 2008 20:31:37 IST
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but i dont understan why dou take deviation between incident ray and reflected ray. whendeviation means angle between incident ray and refracted ray
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5 Sep 2008 20:36:56 IST
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no reply
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5 Sep 2008 20:37:26 IST
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kushi12 why dont u post the right answer pls
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5 Sep 2008 20:37:48 IST
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ans is 180-2c
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