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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:11:03 IST
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An object is placed at a distance of 20 cm from a convex mirror of focal length 20 cm. If the object is made to move away from the mirror with a speed of 5 cm/s, find the speed of image with respect to pole of the mirror.
plz justify ur answer as well.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:24:31 IST
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is the answer 0.01cm/s towards the mirror
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the ost cud have been less colourful just use the formula 1/v + 1/u=1/f and diff both sides with respect to t
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KVS
EP@IITM
Godav,IITM |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:29:05 IST
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ya differentiate the equation
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:30:10 IST
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how ???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:31:07 IST
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tell me if my answer is correct
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:38:15 IST
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i get the answer as 1 cm/s away from mirror.
ashish kindly check ur answer as it will definitely be away form mirror as when obj is at infinity , image is at focus.
c'mon guys ? \ the procedure
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:41:52 IST
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i would like to enquire if the above question can be solved without calculus................??????????????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 15 Apr 2008 17:55:58 IST
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f is constant
so we get
-1/v^2*dv/dt=1/u^2*du/dt
so we get dv/dt=-v^2/u^2*du/dt
calculate v by formula
put the values n get d ans............................
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Apr 2008 17:51:37 IST
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answer is 0.01cm from convex mirror
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