Optics

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2 Oct 2008 17:28:28 IST
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Hcv question
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Question no. 13 page 413 geometrical optics.


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vignesh  the cooler version of newton's Avatar

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2 Oct 2008 17:49:31 IST
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can you plzz tell me the question..
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2 Oct 2008 17:50:59 IST
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 Let distance between S and M2 be 'd' so that total distance is 30+d.


Now,for M2-  f=20


                       u=-d=>v=20d/(20+d) to the right of M2


Therefore, 


for M1, since image formed at S itself,


u= -((30+d)+ 20d/(20+d))


         distance


       from M1


         to M2


v=-30


f=-20


Therefore,


d2 + 10d-600=0=>d=20=>distance = 50cm


 




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