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vignesh the cooler version of newton
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Joined: 16 Mar 2008
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2 Oct 2008 17:49:31 IST
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can you plzz tell me the question..
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2 Oct 2008 17:50:59 IST
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Let distance between S and M2 be 'd' so that total distance is 30+d.
Now,for M2- f=20
u=-d=>v=20d/(20+d) to the right of M2
Therefore,
for M1, since image formed at S itself,
u= -((30+d)+ 20d/(20+d))
distance
from M1
to M2
v=-30
f=-20
Therefore,
d2 + 10d-600=0=>d=20=>distance = 50cm











