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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2008 20:59:52 IST
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Please solve the question no 40 or the last question of the ray optics of ncert text book part II
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2008 21:07:41 IST
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Please post the complete question here itself.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Feb 2008 15:01:09 IST
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An equiconvex lens with radii of curvature of magnitude r each is put over a liquid layer poured on top of a plane mirror. A small needle with its tip on the principle axis of the lens is moved along the axis until its inverted real image concides with the needle itself. The distance of the needle from the lens is measured to be 'a'. On removing the liquid layer and repeating the experiment the distance is found to be 'b'. Given that two values of distances measured represent the focal length values in the two cases, obtain a formula for the refractive index of the liquid.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2008 12:17:31 IST
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Please replyyyyyyyyyyyyyyyyy.................. someone my boards are on the head.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2008 17:20:27 IST
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when there is liquid the lens acts as a planoconcex lens with R1=R(RADIUS OF CURVATURE OF CONCEx LENS) R2=INFINITY(PLANE SURFACE) THE FOCAL LENGHT OF THE COMBINATION IS GIVEN BY; 1/F=1/f1+1/f2 where f1=f of convex lens f2=focal lenght of liq lens 1/f2=(n-1){1/R1-1/R2) =(n-1)/R1 in the problem a=F and b=f1 so solve for f2 and substitute it in the eqn and then u'll get an expression for n
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2008 17:22:41 IST
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i hope it is clear
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2008 21:00:01 IST
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Please explain it more clearly and in detail.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 14:14:09 IST
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when there is water below the lens it acts as a planoconvex lens and when the object coincides with the image it impies it is the focal length of the combination this can be understood frm the ray diagram... and when there is no liq it wud b the focal length of the convex lens because of the presence of plane mirror...... u'll understand it by drawing the ray diagram....... and from this the above follows
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2008 14:34:33 IST
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HERE IT IS... I HAVE DONE IT BY TWO METHODS.....NONE OF THEM ARE IN THE NCERT BOOK....PLS DOWNLOAD THE IMAGE FOR MORE CLARITY...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Mar 2008 14:35:28 IST
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here goes the second method..
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