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Blazing goIITian

Joined: 5 Nov 2007
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29 Apr 2008 17:00:23 IST
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Mirrors and motion-assignment question
None

Question from my school assignment :


A car is fitted with a convex mirror of focal length 20cm.A second car is 6m away from this mirror.The latter starts overtaking with a relative velocity of 15m/s.How fast does the image move and in which direction?


Is the answer 0.14m/s?


Kindly give full solution..


Rates assured :-)


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Celestine Preetham's Avatar

Hot goIITian

Joined: 24 Apr 2008
Posts: 163
29 Apr 2008 20:26:19 IST
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ans is 15\(29^2)

partially differentiate mirror eq to get ans
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Blazing goIITian

Joined: 5 Nov 2007
Posts: 507
30 Apr 2008 16:59:37 IST
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I  differentiated and got 0.015m/s..yours comes to 0.017m/s


or is there some mistake in my differentiation?


1/f=1/u+1/v


Differentiating wrt distance,


0=(du/dx)(-1/u^2)-(dv/dx)(1/v^2)


So


(dv/dx)(1/v^2)--15/u^2


dv/dx=-15*(v/u)^2


       = -15(0.19/6)^2


          =0.015m/s

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Blazing goIITian

Joined: 5 Nov 2007
Posts: 507
30 Apr 2008 17:00:57 IST
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My initial answer was 0.014...by mistake typed it as 0.14..


anyway,did i make a mistake somewhere?


Thanks!:-)

Gaurav |spideyunlimited| Ragtah's Avatar

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Joined: 16 Dec 2006
Posts: 3373
30 Apr 2008 17:20:57 IST
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well I'm getting the same answer as you.
0.015 m/s
Celestine Preetham's Avatar

Hot goIITian

Joined: 24 Apr 2008
Posts: 163
30 Apr 2008 19:22:18 IST
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learner the error u made is finding V as .19 Its .1973684211
put V as UF/U-F to avoid approx
Gaurav |spideyunlimited| Ragtah's Avatar

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Joined: 16 Dec 2006
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1 May 2008 00:10:36 IST
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yaar i used calculator still it comes as 0.015something
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Blazing goIITian

Joined: 5 Nov 2007
Posts: 507
1 May 2008 23:22:59 IST
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Ok thanks guys...


The basic method is correct,right..I guess 0.015 and 0.017 difference can be neglected..


Thanks again!!




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