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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 May 2007 21:07:06 IST
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Check this out!!!!!!!!!!!!!!! A particle is moving at a constant speed v from a large distance towards a convex mirror of radius R along its principal axis . Then try to find out the speed of the image formed by the mirror as a function of the distance x of the particle from the mirror.In fact a same type of question is there in H.C.VERMA.
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2007 04:55:50 IST
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Lemme have a go :
Let the distance of the particle from the mirror be x. We are given dx/dt = v.
If v is the image distance, we've got to find dv/dt.
Now, since we are given R, using lens maker's formula,. we can get f :
1/f = (1-M)(2/R) (M for glass is 1.5)
Now, Using mirror formula, 1/v-1/u=1/f, and differentiating both sides with respect to time, (here f is a constant), You should get the required result.
Am I right or what?
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Will nip in at times to solve problems :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2007 06:02:33 IST
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hai guys .....................the speed of the image wrt the mirror is also v..........but wrt object the ans is 2v need not differentiate................use numbers to get it
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 May 2007 14:21:13 IST
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Phyana, you are wrong. The speed of the image is not v. V is the distance of the image from the principal focus.
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Will nip in at times to solve problems :)
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