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Blazing goIITian

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23 Aug 2008 17:14:35 IST

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anchit saini

Blazing goIITian

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23 Aug 2008 17:15:19 IST

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click on image to see the qn completely

Chirag Sangani

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Joined: 12 Dec 2007

Posts: 611

23 Aug 2008 18:53:21 IST

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It is clear that the relative velocity will only be perpendicular to the axis

1 / v + 1 / u = 1 / f

so,

v = uf / u+f

I = O v / u

I = (0.5 cm) f / (f + u)

dI/dt = -(0.5cm) f / (f + u)^2 * du/dt

Putting f = 40 cm and u = -30 cm, du/dt = 4cm/s,

|dI/dt| = 0.8 cm/s = v

This is the speed with which one image will approach the principal axis. However, since we want relative velocity, we need the double of v which is 1.6 cm/s

anchit saini

Blazing goIITian

Joined: 1 Feb 2008

Posts: 1251

23 Aug 2008 19:02:37 IST

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i took u =+ 30 , damn damn

anyways thanks

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