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8 Jan 2009 18:31:34 IST

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435

perplexing interference paradox

None

for 2 coherent sources , I net =(√I1 + √I2)² wen path diff = 0

now take these 2 and separate them like interference exp , you get max , min but avg intensity remains I1 + I2

now if u put these 2 sources together , path diff always 0 , hence always max given by eq abv . but here Inet ≠ I1 + I2

why

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Prakhar Banga

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8 Jan 2009 18:37:28 IST

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When you put them together, the Inet should be the maximum in the above case, i.e. (√I1 + √I2)², and not (I1 + I2), which is the average. What don't you understand?

Celestine Preetham

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9 Jan 2009 13:52:19 IST

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energy conservation is violated

Aakash !

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Joined: 12 Jan 2009

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16 Jan 2009 14:41:18 IST

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when you keep both the coherent sources togather path differebce would be zero. hence accordingly intensity will be max. ie. .

is the average intensity on the screen.

practically, when you enter in a dark room with two torch. light first torch & focus on the wall. now light second torch & & focus it on the wall at the same place. you will find brightness of the circular fringe has increased.

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