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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jan 2008 00:47:38 IST
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A glass rod of thickness d [ diameter ] is bent in the form of a circle as shown in figure such that the radius of the circle is R. Refractive Index of glass is 1.5 Find, the max value of d/R so that the ray entering from A normally, exits from B. a) 2 b) 0.5 c) 1.41 d) 0.41 I will post the answer afterwrads. please do solve it....... a pic has been attached to assist my friends !!
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My birthday is no ordinary day.
Its the day when i declared in my own voice,
I WILL NOT GO QUIETLY INTO THE NIGHT,
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Jan 2008 15:26:29 IST
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is da ans 0.5 tell me if rit i can xplain
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jan 2008 20:55:41 IST
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Yeah, its correct. please post the solution.
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My birthday is no ordinary day.
Its the day when i declared in my own voice,
I WILL NOT GO QUIETLY INTO THE NIGHT,
I WILL NOT VANISH WITHOUT A FIGHT,
I AM GOING TO LIVE ON,
I AM GOING TO SURVIVE,
I AM GOING TO GET WHATEVER I WANT.
I CELEBRATE MY BIRTHDAY, AS MY INDEPENDENCE DAY !!!!!!!!! |
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for the ray to leave at B, it is essential that the first incidence of light from A in the tube be at an angle greater than the critical angle so that TIR takes place. By symmetry, it can be proved that the rest of the reflections will also be TIR when it leaves from B.
the limiting case would be when the incidence angle is the critical angle. from the figure, sin A = r/(r+d) = 2/3 (sin of critical angle = 1/ ) hence, d/r = 0.5
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"A perfect mind is a treasure unsurpassed."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Jan 2008 19:26:07 IST
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oh! sorry dude astatine19 posted the solution before i cud neways his soln is da same as mine. keep postin gud questions.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Jan 2008 00:15:33 IST
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Well yaar, actually, i got the answer myself today in the morning, just thought to confirm,if i was right !! Anyways, thanks a lot !!!!
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My birthday is no ordinary day.
Its the day when i declared in my own voice,
I WILL NOT GO QUIETLY INTO THE NIGHT,
I WILL NOT VANISH WITHOUT A FIGHT,
I AM GOING TO LIVE ON,
I AM GOING TO SURVIVE,
I AM GOING TO GET WHATEVER I WANT.
I CELEBRATE MY BIRTHDAY, AS MY INDEPENDENCE DAY !!!!!!!!! |
this reply: 5 points
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