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22 Feb 2008 21:33:59 IST

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regarding number of images?

None

how is no. of images formed when an object placed between 2 mirrors inclined

at an angle"w" be 360/"w"-1?

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GAURAV SHARMA

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Joined: 7 Aug 2007

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22 Feb 2008 21:47:28 IST

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SEE WHEN AN OBJECT IS PLACED SYMMETRICALLY AND THE VALUE 360/w IS EVEN THEN THE NO. OF IMAGES ARE 360/w - 1..LET ME EXPLAIN U WITH THE HELP OF AN EXAMPLE..
TAKE w TO BE 60. THEN 360/60 = 6..NO OF IMAGES WILL BE 5 BECAUSE WE CONSIDER ALL THE IMAGES ON A CIRCLE WITH CENTRE BEING THE POINT OF INTERSECTION OF THE MIRRORS.NOW SINCE WE GET 360/60=6 THAT MEANS THERE ARE SIX SYMMETRICAL POINTS WHERE THE IMAGE AND OBJECT IS. ONE POSITION IS OCCUPIED BY THE OBJECT THUS THE OTHER 5 PLACES WILL BE OCCUPIED BY THE IMAGES.
WHERE AS IF 360/w IS ODD AND THE OBJECT IS PLACED SYMMETRICALLY THEN ALSO THE SAME POLICY IS FOLLOWED BUT IF THE OBJECT IS NOT SYMMETRICAL THEN THE NO. OF IMAGES ARE 360/w BECAUSE HERE THE CIRCLE THEOREM CANNOT BE FOLLOWED.HERE ONLY RAY DIAGRAMS CAN HELP.
BY SYMMETRICAL POSITION OF THE OBJECT I MEAN THAT THE OBJECT IS ON THE ANGLE BISECTOR OF THE ANGLE B/W THE MIRRORS.

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Soumen Goswami

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Joined: 10 Apr 2007

Posts: 1777

23 Feb 2008 08:25:49 IST

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Excellent answer @gaurav3sharma

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