IIT JEE , AIEEE Forum - Physics , Optics

nasa_hs

In young's double slit interference experiment the incident light consists of 2 wavelenghts $\lambda$ ₁ & $\lambda$ ₂& the slit separation d & D is the distance between the slits & the screen.The maxima due to the two wavelenghts will coincide at a dist from the central maximum which is

$\lambda$ ₁+ $\lambda$ ₂/2(D/d)

$\lambda$ ₁- $\lambda$ ₂/2(D/d)

Least common multiple of $\lambda$ ₁D/d and $\lambda$ ₂D/d

Highest common multiple of $\lambda$ ₁D/d and $\lambda$ ₂D/d

ans is c

pink_ele

fringe width r respectively
lambda 1D/d and lambda 2 D/d
the maxima will coincide again when ....
let suppose after m fingesn n fringes d fringes of both overlap .......
that means ....after.....LCM of both d fringe widths ........
hence d ans

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