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Analytical Geometry

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11 Mar 2008 13:33:54 IST

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points A and B are specified by the position vectors a and b. prove that eqn of plane bisecting the segment perpendicularly is

r.(a-b)=1/2 ( |a|^2 - |b|^2)

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Sai Ganesh Bandiatmakur

Hot goIITian

Joined: 17 Feb 2007

Posts: 138

11 Mar 2008 18:00:50 IST

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EaSy !

See since the required plane bisects the segment..I think it perpendicularly bisects is what u mean... Normal vector to required plane is

(a-b) so let the eqn of plane is
r.(a-b)=p. To find p, substitute (a+b)/2 in place of r as their midpt lies on the plane. u get the ans.

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