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Analytical Geometry

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25 Oct 2007 21:06:14 IST

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A DAS GUPTA

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A BEAM OF LIGHT IS SENT ALONG THE LINE X-Y=1 WHICH AFTER REFRACTING FROM THE X-AXIS ENTERS THE OPPOSITE SIDE BY TURNING THROUGH 30 DEGREE TOWARDS THE NORMAL AT THE POINT OF THE INCIDENCE ON THE X-AXIS.FIND THE EQUATION OF THE REFRACTED RAY.

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Bipin Dubey

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Joined: 23 Jan 2007

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25 Oct 2007 21:20:02 IST

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x-y = 1 makes an angle of 45⁰ with x-axis.
It intersects x-axis at (1,0).

Since the ray turns 30⁰ towards normal line, it turns 30⁰ away from the x-axis. So the refracted ray makes an angle of 45⁰+30⁰ = 75⁰ with x-axis.

Also it passes through (1,0).

So equation of refracted ray : y = tan75⁰.(x-1)

divya jyothi

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26 Oct 2007 13:47:04 IST

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The problem can be solved even using transformation eqs i.e X=xcos30+ysin30,Y=ycos30-xsin30.Substitute instead of (x,y):(1,0) &(0,-1).Then find the corresponding values of (X,Y) and use two pt. form and find the eq.

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