centre lies on y = x-1 o centre is (k,k-1)

eccentricity is square root 2 since its rectangular..............now for asymptotes they r given by X +/-  Y = A where A is the semi major axis or semi minor axis they r the same here anways!!

Now try it out!!!

hi friend it was really a good q

you know that the asymtotes passes through the centre of the rectangular hyperbola and also the asymtotes of rectangular hyperbola are at 90 to each other hence the centre you will get by solving the two equation is (-2,-3)

and will the asymtote will have slope -4/3

and now you can eazily find the equation

bye

plzz rate me

 

indeed it is a good quesion but i have one doubt

suppose we shift our origin to the centre of the hyperbola which is (2,0)

now the equations 3x-4y-6=0

becomes 3X - 4Y = 0.........................(X,Y ) are the new co-ordiante axes

on comparing this with

X/a (+ -) Y/b =0

we get a = 1/3 and b = 1/4

but since it is rectangular a should be equal to b but we can see it is not .

so why is this contradiction .

someone plzzzzzzzzzz. help  

hi aman ,

thanxx i like ur ans it is not the complicated one...

it is a simple one.....