Let the triangle be ABC and the centre of the circle be O.
Therefore, angle AOB = 120 degrees and angle ABO = 30 degrees.
So By sine rule
AO is the radius. Let it be r. AB is the side of the triangle. Let it be a.
So a = r.
That means the radius of the circle is
The side a is therefore .
The area of the triangle is =
the radius of the circle with given equation is :
r = (g2 + f2 - c)1/2
for equitlateral traingle
r = a / root(3)
area of traingle = root(3) / 4 * a2
now solve it ,you will get the answwer
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