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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Feb 2007 18:59:20 IST
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the line 4x+ 3y - 4=0 divides the circumference of the circle with centre at (5,3) in the ratio 1:2. then find the equation of the circle......
in this question, one method is to homogenise the circle's equation n then find the angle b/w the line joining the given line nd thus finding the radius.... but its quite lengthy(as circle is not standard one).... neone with ne method????
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Manasi....
NIT-Allahabad...
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21 Feb 2007 19:34:26 IST
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hi
the distance of line from centre comes out to be 5
let cirumference be divided into x and 2x so x comes otu to be
2(pie)r/3
this implies that the minor arc subtends an angle 2(pie)/3
= 120 degrees
connect the two points of intersection on the circle to centre
let radius be r
so angle made at the intersection points by radius and given line is 30 degrees (remember the angle at centre is 120)
so rsin30 = 5 (distance from centre)
so r = 10
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21 Feb 2007 19:49:20 IST
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rik_mad is perfect!!!!!
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ADARSH
NITK Surathkal
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22 Feb 2007 19:25:47 IST
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well done rik_mad
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