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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 13:49:14 IST
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A circle 'C' whose radius 1 unit,touches the X-axis at pt.'A'.the centre 'Q' of 'C' lies in
1st quadrant.the tgt from origin 'O' to the circle touches it at 'T'and a pt. 'P' lies on this tgt such that OAP is a right angled triangle with right angle at 'A' &its perimeter is 8 units
wat is length of QP
(a)1/2units (b)4/3units (c)5/3 units (d)7/3units
pls explain with soln
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11 Apr 2008 13:51:30 IST
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the answer is 5 /3
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11 Apr 2008 16:42:22 IST
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thats right
gimme the soln pls
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12 Apr 2008 08:50:42 IST
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pls reply soon
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12 Apr 2008 10:05:36 IST
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even i know that 5/3 is the answer pls post the soln
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12 Apr 2008 10:23:30 IST
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??
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Here I am this is ME!!...and there's no where else on earth I'd rather be!!!!!! |
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12 Apr 2008 10:25:55 IST
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QP= 7-(pt+2oa).....
wat will the values..of oa and pt be??
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12 Apr 2008 10:56:48 IST
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the perimetergiven - perimeter of trngle?
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12 Apr 2008 12:40:42 IST
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pls. help!!
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A -->(a,0) Q--->(a,1) P--->(a,t) T--->cos@,sin@...{parametric co-ordinates of a circle} Perimeter = a+t+((a^2+t^2)^1/2)=8.....(1) tan@ = t/a....(2) solve the 3 equations with unknowns a,t and @
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