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Analytical Geometry

sudiv divakar's Avatar
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Joined: 1 Dec 2007
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14 Jan 2008 08:16:33 IST
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circles
None

the equation of tangents drawn from the origin to the circle  x*2+y*2-2rx-2hy+h*2=0
are:


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sowjanya gudipati's Avatar

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Joined: 13 Oct 2007
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14 Jan 2008 12:59:56 IST
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Re:circles
Rahul Raghavendra's Avatar

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Joined: 9 Jan 2008
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14 Jan 2008 13:17:18 IST
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since eqn of circle is x^2+y^2-2rx-2hy+h^2=0
comparing it by standard eqn ,x^2+y^2+2gx+2fy+c=0
we get
 it's centre as (r,h) and radius as r
 
now ,let the eqn of tangent be y=mx+c.
since it is passing through origin ,eqn will reduce to y=mx.
 
now
 
length of perpendicular from centre of circle to tangent = radius of circle.
 
(mr-h)/1+m^2        =r.
 
therefore from this  u obtain m=(h^2-r^2)/2rh
 
 
eqn of tangent will be y={(h^2-r^2)/2rh}x
 
 
 
rate me if correct
 
 



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