| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Dec 2007 22:16:47 IST
|
|
|
2 circles x^2+y^2=6, x^2+y^2 - 6x +8=0 are given. Then the equation of the circle thru their point of intersection and the point (1,1) is- Ans---> x^2+y^2 - 3x + 1=0 I called this ''ajeeb'' becoz, if you find the point of intersection of these 2 given circles by putting x^2+y^2=6 in the second equation, we get x= - +7/2. Now you keep this value in the equation x^2+y^2=6, you get y^2= -25/4 which is not possible. It means that their point of intersection does not exist. Then how come the answer came? Please help Rates assured.
|
The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
|
|
|
19 Dec 2007 22:21:08 IST
|
|
|
question is wrong because only oneline can be drawn thats the radical axis.(1,1) does not satisfy it check it out
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
19 Dec 2007 22:21:30 IST
|
|
|
clearly C_{1}:(0,0) r_{1}=root(6)
C_{2}:(3,0) r_{2}=1
C_{1}C_{2}=3 <1+ root(6) So the circles have to intersect at real points
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
19 Dec 2007 22:25:15 IST
|
|
|
(1,1) is a point inside the first circle and outside the second
why doesn't it satisfy the equation
for 1st it is 2 and for second also it is 2
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
19 Dec 2007 22:29:14 IST
|
|
|
Abe yeh to theek hai ki circles have to intersect at real points but why I am not getting real points by solving the circles? How to do this question?
|
The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Dec 2007 03:12:45 IST
|
|
|
tarin please do mind ur language while typing come straight to the point no need of anointing
well u have done a silly mistake
putting x^2+y^2=6
in the second equation gives
6-6x+8=0 this gives 14=6x so x=7/3 and not 7/2
rest everything is fine
|
this reply: 10 points
(with 2
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Dec 2007 13:59:54 IST
|
|
|
Hey pardesi,
yaar bura kyon maan gaye? I AM SORRY. Khush!
Thanx for solving the question. Here's ur 5 pointer.
|
The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
20 Dec 2007 14:08:54 IST
|
|
|
no probs 
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
25 Dec 2007 16:33:32 IST
|
|
|
the answer is correct because if getting the negative value of y
then it means that it is intersecting in the coordinate where
y is negative ..... it doesnot means that circle donot intersect each other
|
I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME. |
this reply: 2 points
(with 0
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
