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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: circles:sqb..solution reqd...
Forum Index -> Analytical Geometry like the article? email it to a friend.  
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sharmadon (2)

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tangents at the points (a cos(theta), a sin(theta) ), and (a cos(theta + pie /3), a sin(theta + pie/3) ) on a circle x^2+y^2= a^2 are drawn.then what is the locus of intersection of these tangents?
    
akshay.khare91 (395)

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the locus is the MOJOR ARC OF A CIRCLE
that is we can say that it is a circle..

if my ans . is right plss tell i can give u solution..

I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME.
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RyuAmakusa (449)

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i guess that will also be a circle
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ankitagg (165)

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the locus is 3x^2+3y^2=4a^2
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sharmadon (2)

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yes its a circle..now pls post ur solutions...
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ankitagg (165)

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cospie/6=a/IO
root3/2=a/x
x=2a/root3

now h^2+k^2=x^2
h^2+k^2=4a^2/3
3h^2+3k^2=4a^2
3x^2+3y^2=4a^2 ans.
see my next post for its diagram
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akshay.khare91 (395)

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underoot of  root3/2=a/x
x=2a/under root of 3

 h+ k= x
 h2 +  k= 4a2 / 3

 3h2 + 3k= 4a2               -- ans..

I DONOT FOLLOW THE RULES I MAKE THEM TO FOLLOW ME.
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RyuAmakusa (449)

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yeah the ans is correct. i made a calc. mistake
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