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Analytical Geometry

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10 Nov 2007 09:19:42 IST

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circles very basic ques!!!! rates assured....

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two circles x^2 + y^2 =6 and x^2 +y^2 -6x+8=0 are given.then the equation of the circle passong through their points of intersection and the point(1,1) is.......

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kishore subramanian

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Joined: 21 Apr 2007

Posts: 453

10 Nov 2007 09:34:39 IST

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let the equn of the clrcle passing through the intersection of two circles be

(x^2 + y^2 -6)+k(x^2 +y^2 -6x+8)=0 (k

-1)

it passes through (1,1)

(1+1-6)+k(1+1-6+8)=0

k=1

hence the equn is x^2 + y^2-3x+1=0

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