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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Dec 2007 20:32:15 IST
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If normals are drawn to the ellipse x2 + 2y2 = 2 from the point (2,3), then the co-normal points lie on the curve-? Ans-xy+3x-4y=0 Salutes assured.
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13 Dec 2007 20:45:17 IST
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Dude, y do u give the answer along...??????
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13 Dec 2007 20:46:13 IST
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Plz explain wat co-normal pts. are????
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13 Dec 2007 20:58:56 IST
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I gave the answer so that you can check ur answer before posting the solution.
Conormal points are those points, the normals at which pass thru a same point. eg-P,Q,R are conormal points if normals at P,Q,R pass thru a same point S.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
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13 Dec 2007 21:12:30 IST
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So which co-normal pts r v talking abt in the question??
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13 Dec 2007 21:13:55 IST
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Arre wohi to question hai.
You have to assume conormal points from urself and then you have to find their locus.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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Back to goiit, this time with Baby Veerappan. :D |
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13 Dec 2007 21:15:04 IST
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From a given point not on the curve, we can draw 3 normals. SO we have to find their locus I think.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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13 Dec 2007 21:19:08 IST
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So wat does the give info have to do with that........?????
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13 Dec 2007 21:21:11 IST
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eqn of normal is to ellipse is a^2x/x1 - b^2y/y1 = a^2-b^2
(x1,y1) is the point of intersection of normal n ellipse
in this ellipse a=rt(2), b=1
so normal is 2x/x1 - y/y1 = 1
it passes thru (2,3)
so 4/x1 - 3/y1 = 1
hence locus of x1,y1 is xy + 3x - 4y = 0
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13 Dec 2007 21:22:22 IST
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Thanx rahul.
Here's ur salute.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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13 Dec 2007 21:23:40 IST
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rhd, plz xplain the Q..
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13 Dec 2007 21:28:49 IST
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Guys,
please have a look at this also-
http://www.goiit.com/posts/list/geometry-ellipse-1-34784.htm
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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13 Dec 2007 21:30:54 IST
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Jatin, the question says,
you have to find the locus of the points where the normals from the given point intersect the ellipse.
So rhd took a general point of intersection (x1,y1) and by using the equations of normal he found the locus of (x1,y1)
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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13 Dec 2007 21:36:03 IST
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Another good question-
http://www.goiit.com/posts/list/geometry-ellipse-2-34785.htm
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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