Suppose foci are S (ae,0) and S' (-ae,0) and extremity of the minor axis be P(0,b).
slope of PS = -b/ae and slope of PS' = b/ae
since they are perpendicular the product of their slopes must be -1.
(-b/ae)(b/ae) = -1
e2 = b2/a2
Also we know for ellipse : b2/a2 = 1 - e2
hence e2 = 1 - e2
e = 1/root(2)