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jw (0)

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1) if sum of 84 members first of the series
(4+[ ] 3  /   1 + [ ] 3 ) + (8+ 15  /  3 + 5 ) +  ( 12 + [ ] 35 /  [ ] 5 + [ ] 7 ) +......

is????????


2)  if x and y are real nos satisfing x^2 + y^2 - 6x + 8y + 24 = 0
the gretest value of 16/5 cos^2 ([ ] (x^2 + y^2) ) - 24/5 sin ([ ] (x^2 + y^2) ) is???


3) when 23 23  is divided by 53 the reminder is 5k.
k is??

4) let f(x) = ax^2 + bx + c and g(x) = Ax^2 + bx +K where a 0 A not equal to 0
a, b c A k is   R

roots of f(x) =0 and g(x) =0 are imaginary then

f(x)/a + g(x) /A >0  for all  x belongs to  R

how???







    
Conjurer (529)

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4)

Since roots are imaginary, the functions do not cut the x axis.It lies either above the axis(if a/A > 0) or below the axis (if a/A <0).In either case f(x)/a + g(x)/A >0




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jw (0)

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please someone try
the other Questions
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ananth_patri (585)

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for 3) is the answer k=6??

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ananth_patri (585)

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well the process is this way... write 2323 as 23(23)22 and now
 
=23(529)11 =23(530-1)11 ,.... all the binomail exp tyerms will be in the form 53k ....the last 2 terms are 11C10 530 - 11C11   ... so this will make as ...23(53k-1)/53 which ...thus we get it as n - 23/53.....now we can get it as 30/53 on makin the left term positive....thus remainder is 30 which is 5*K thus K=6.. hope u got it ...rate if useful....

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ankitagg (236)

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ananth will u please tell me what does [ ] this mean in his question.

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dream (571)

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@ankitagg
it is nothing
it is just a symbol that it is square root , ie, to the power 1/2
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anchitsaini (4290)

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1) \\ \\ \mbox{on rationalising the denominator }\\ \\ T_1 = \frac{(4 + \sqrt{3})(1 - \sqrt{3})}{-2}\\ \\ \mbox{on opening brackets we get }\\ \\ T_1 = \frac{1 - 3\sqrt{3}}{-2}\\ \\ \mbox{similarly we get }\\ \\ T_2 = \frac{3\sqrt3 - 5\sqrt{5}}{-2} \\ \\ T_3 = \frac{5\sqrt5 - 7\sqrt{7}}{-2} \\ \\ \mbox{or T_r } = \frac{(2n-1)\sqrt{2n-1} - (2n+1)\sqrt{2n+1}}{-2}  \\ \\

\mbox{ therefore series comes something like }\\ \\ \frac{1 - 3\sqrt{3} + 3\sqrt{3} - 5\sqrt{5} ....(2n-1)\sqrt{2n+1} - (2n+1)\sqrt{2n+1}}{-2}\\ \\ \sum_{r=1}^{n}T_r= \frac{1 - (2n+1)\sqrt{2n+1}}{-2} \\ \\ \mbox{here } n = 84 \\ \\ \mbox{ hence answer is }\frac{1 - 169\sqrt{169}}{-2} = 1098

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