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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 12:25:23 IST
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FIND the area of quadrilateral ABCD whose vertices are given as (-3,2) (7,6) (-5,-4) (5,4).
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 12:37:37 IST
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find the area of two triangles........ and add them to get the area of quadrilateral........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Mar 2008 21:20:56 IST
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use the method of determinants solve it like this | | = stands for determinants
| x1 y1| + | x2 y2 | + | x3 y3 | + | x4 y4 | | x2 y2 | | x3 y3 | | x4 y4 | | x1 y1 |
= (x1y2 - x2y1) + (x2y3 - x3y2) + (x3y4 - x4y3) + (x4y1 - x1y4)
put values and get the ans..
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