|
| physics chemistry maths science forums |
|
|
|
| |
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 May 2008 11:22:50 IST
|
|
|
Find the area of pentagon with vertices A(1,1),B(7,21),C(7,-3),D(12,2) and E(0,-3) as a su
|
|
|
|
14 May 2008 11:30:46 IST
|
|
|
Is the ans 113/2 sq.units.I will explain if i am correct.
|
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
14 May 2008 21:29:40 IST
|
|
|
That is simple.
As coordinates of all 5 vertices of pentagon are given thus we can divide the pentagon into 3 triangles.
Thus area of pentagon = Sum of area of the three triangles
|
The most incomprehensible thing about the world is that it is
at all comprehensible. |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
14 May 2008 21:31:23 IST
|
|
|
The (signed) area of a planar triangle specified by its vertices  for  , 2, 3 is given by
|
The most incomprehensible thing about the world is that it is
at all comprehensible. |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
