|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2008 00:40:06 IST
|
|
|
how to find that d pt.(x,y) will lie in d acute angle or obtuse amgle bisector of d 2 in
|
|
|
|
10 Feb 2008 00:41:50 IST
|
|
|
-tersecting lines. dont give d formula just give d concept 4 finding
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
10 Feb 2008 02:23:26 IST
|
|
|
?????????????
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
10 Feb 2008 07:04:51 IST
|
|
|
find the equation for the two bisectors(i think you know how to find if not you may ask)and substitute values of(x,y) in them if satisfying the eqn.they lie on it
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
    
<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
10 Feb 2008 11:45:05 IST
|
|
|
See,It can be solved using the concept of position of a point relative to a line,and using the equation of angle bisectors,Say (@,#) is ur point,
Then,
The general Equation of the bisector containing (@,#) is the +ve eqn or neg eqn(of the bisectors) according as a@+b#+c and p@+q#+r have the same sign or otherwise,where ax+by+c and px+qy+r are the lines whose bisector is in question..
Pls Rate if satisfactory!
|
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
