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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2007 13:52:42 IST
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If each of the points (a,4),(-2,b) lies on the line joining the points (2,-1), (5,-3) then the point (a,b) lies on the line? note: answer should be in equation
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BALA |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2007 14:00:10 IST
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The equation of the line joining the points (2,-1) and (5,-3) is (y+1) / ( x - 2) = (-3 + 1) / ( 5 - 2 ) = - 2 / 3 i.e 2x + 3y = 1 Since the points (a,4) and (-2, b) lie on the above line, then, 2a + 12 = 1 i.e a = -11 / 2 Again, -4 + 3b = 1 i.e b = 5 / 3 Therefore (a,b) is ( -11 / 2, 5/3) Cheers!! Do rate me !!!
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You never know what is enough till you know what is more than enough.
Titun |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2007 14:02:34 IST
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the point comes out to (-11/2,5/3) any options given?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2007 14:17:43 IST
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yes
(a,b) is (-11/2,5/3)
whatever line satisfies this for x,y is the right option
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 May 2007 15:58:25 IST
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Equation of line joining (2,-1) and (5,-3) :
y+1 = {(-1+3)/(2-5)}.(x-2) 2x + 3y = 1
Since (a,4) and (-2,b) lies on it , they will satisfy the the above equation.
2a + 3(4) = 1 a = -11/2
2(-2) + 3b = 1 b = 5/3
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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