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balaandsachin (0)

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If each of the points (a,4),(-2,b) lies on the line joining the points (2,-1), (5,-3) then the point (a,b) lies on the line?
note: answer should be in equation

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titun (1529)

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The equation of the line joining the points (2,-1) and (5,-3) is
 
(y+1) / ( x - 2) = (-3 + 1) / ( 5 - 2 ) = - 2 / 3
 
i.e 2x + 3y = 1
 
Since the points (a,4) and (-2, b) lie on the above line, then,
 
2a + 12 = 1 i.e a = -11 / 2
 
Again, -4 + 3b = 1 i.e b = 5 / 3
 
Therefore (a,b) is ( -11 / 2, 5/3)
 
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jainmonal (0)

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the point comes out to (-11/2,5/3) any options given?
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thevyzz (332)

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yes

(a,b) is (-11/2,5/3)


whatever line satisfies this for x,y is the right option
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iitkgp_bipin (6498)

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Equation of line joining (2,-1) and (5,-3) :

y+1 = {(-1+3)/(2-5)}.(x-2)
2x + 3y = 1

Since (a,4) and (-2,b) lies on it , they will satisfy the the above equation.

2a + 3(4) = 1
a = -11/2

2(-2) + 3b = 1
b = 5/3

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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