IIT JEE , AIEEE Forum - Mathematics , Analytical Geometry

m.viddya

Q.The equation to the conjugate hyperbola of xy+3x-4y+13=0 is?

1.(x-4)(y+3)

2.(x-4)(y+3)=0

3.(x-4)(y+3)=25

4.xy+x-4y-13=0

Greatdreams

Eqn of the hyperbola xy + 3x - 4y + 13 = 0

So x(y+3)-4(y+3) = -13-12 = -25

so (x-4)(y+3) = -25

or (x-4)(y+3)+25 = 0

Since we know that eqn of hyperbola + eqn of conjugate

= 2*(eqn of asymptotes)

So we have eqn of conjugate = (x-4)(y-3) - 25 = 0

So answer c

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