Home » Ask & Discuss » Mathematics. » Analytical Geometry « Back to Discussion



Analytical Geometry

varsha valli g.'s Avatar
Blazing goIITian

Joined: 31 Jan 2007
Post: 515
7 Apr 2008 11:43:12 IST
0 People liked this
7
637 View Post
line eqn:!!!!!!!!!rates assured
None

how to convert a line's eqn from ax+by+c-0 form to x-x1/x2-x1 =y-y1/y2-y1 form
in Q like finding foot of perpendicular v need the 2nd form.
 
plz reply soon
urrrrrrrrrgenttttttttttttttttttt
rates assured
!!!!!!!!!!!!!!!


Share this article on:

Comments (7)

joy francis's Avatar

Blazing goIITian

Joined: 19 Feb 2007
Posts: 1802
7 Apr 2008 11:56:19 IST
1 people liked this

Can u plz post the question..i don't think there is any compulsion on converting the line from this form to that form..
 
waise it is easy ..just take any 2 points satisfying the given line and then put the points in the eqn of two point form to get the eqn..
 
But i don't see any good in doing this..plz post the qn! 
ashish banga's Avatar

Blazing goIITian

Joined: 16 Dec 2006
Posts: 1362
7 Apr 2008 12:01:07 IST
1 people liked this

slope of line = -a/b = tan theta
from tan theta given u can find cos theta and sin theta
this line also passes through a point which can be found by putting x= 0 we can get y coordinate when x =0
equation of line becomes
x - x1/ costheta = y -y1/ sin theta
varsha valli g.'s Avatar

Blazing goIITian

Joined: 31 Jan 2007
Posts: 515
7 Apr 2008 12:32:33 IST
0 people liked this

Q:find the foot of the perpendicular from the pt. (1,2)
to the line 3x+y+1=0.

!!!!!!!!!!
Rahul Raghavendra's Avatar

Blazing goIITian

Joined: 9 Jan 2008
Posts: 843
7 Apr 2008 12:39:36 IST
1 people liked this

Let   x-3y+ \mu =0  be the line perpendicular to 3x+y+1=0  {mu is a constant}
 
Since it passes through (2,1)
It must surely satisfy it.
 
2-3(1)+\mu=0\\\\
\mu=1
 
 
Thus ans is
x-3y-1=0
 
Rahul Raghavendra's Avatar

Blazing goIITian

Joined: 9 Jan 2008
Posts: 843
7 Apr 2008 12:40:15 IST
0 people liked this

solve the two eqn to get the final answer
seraphic's Avatar

Hot goIITian

Joined: 1 Apr 2008
Posts: 124
7 Apr 2008 12:52:13 IST
1 people liked this

foot of perpendicual of a point (x1, y1) on the line ax+by+c=0 can b found using....
[ where (h,k) is the foot of perpendicular]
 
(h-x1)/a  =  (k-y1)/b  = -[ax1 +by1 +c]/(a2+b2)

Scorching goIITian

Joined: 11 Mar 2007
Posts: 268
7 Apr 2008 13:30:27 IST
1 people liked this

see
d lyn perpendicular to line 3x+y+1=0 will hav slope -(1/3)
now we noe d equation of line passing thru point (1,2) nd having slope
-(1/3)
solve this equation with
3x+y+1=0
nd find coordinate




Quick Reply


Reply

Some HTML allowed.
Keep your comments above the belt or risk having them deleted.
Signup for a avatar to have your pictures show up by your comment
If Members see a thread that violates the Posting Rules, bring it to the attention of the Moderator Team
Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor


@ INR 1,995/-

For Quick Info

Name

Mobile No.

Find Posts by Topics

Physics.

Topics

Mathematics.

Chemistry.

Biology

Parents

Board

Fun Zone

Sponsored Ads