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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Line's equation
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magiclko (4210)

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What is the equation of the line passing thru (2,2) and having equal intercepts on th axis??
 
PS : I knw the answer is very easy.... but watevr options were given thr.... x+y=4 wasnt thr .....
    
ashish_banga (975)

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the equation is

x/a + y/b = 1
a = x-intercept
b = y- intercept

acc to the ques.
x/a + y/a = 1
x +y = a
also x + y =4 as it passes thru (2,2)
so ,x + y = 4
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magiclko (4210)

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i said beforhand only.... this wasnt thr in the options...
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himanshu2006 (43)

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since ,THE LINE IS EQUALLY INCLINED TO BOTH AXES.
THEREFORE ,ITS SLOPE WOULD BE 1 OR -1.
NOW,
FIRST EQN.:--

Y-2= 1(X-1)
X=Y OR X-Y=0
SEC.EQN:

Y-2=-1(X-2)
X+Y = 4

PLZ LET ME KNOW WHERE I WENT WRONG'
CHEERS!!!!

HIMANSHU
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magiclko (4210)

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u rnt wrong nehwhere... but this wasnt thr in the options given!!
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himanshu2006 (43)

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CAN U PLZ GIVE ME THE OPTIONS SO THAT I CAN CHECK WHERE I WENT WRONG
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vineet (133)

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hey dont worry may be options in book r wrong.sometimes it happens

Think different .........................think apple
ALBERT EINSTEIN
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rohitju (81)

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yep ,
         i got
                x+y=4
         there must be something wrong with the options.
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magiclko (4210)

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the answer given was x=y.... while solving x+y=4 shud be the only answer
wat i meant to ask here is that are "zero intercepts justified".... i hav asked it frm experts also... see the following post
 

Manasi....
NIT-Allahabad...

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Asmita (475)

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Obviously there are 2 correct ans. : x=y & x+y=4.
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Asmita (475)

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Let the eq. of the required line in the intercept form be x/a  y/b =  1.
Case 1 : when x/a + y/b =1 i.e. the line is going downwards from the left to the right of the cartesian plane.
Here a=b=k(say)
therefore x+y=k
but (2,2) lies on it Therefore 2+2=k=4
therefore the eq. of the line is x+y=4.
Case 2 :when x/a - y/b = 1 i.e. the line is going upwards from the left to the right of the cartesian plane.
Here a=b=p(say)
therefore l(x-y)l=p....(1)
but (2,2) lies on it Therefore 2-2=p=0
therefore from (1) the eq. of the line is x-y=0 i.e. x=y
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shubham_sachdeva (1901)

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DEAR MAGICLKO,
 
 
I HAVE ASKED SOME1 .HE IS SAYING THAT 0 INTERCEPTS R NOT DEFINED.
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magiclko (4210)

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i think its not defined.... but is not sure..... waise, in the question , only x=y was given and not x+y=4, so it must be true!!!

Manasi....
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Challenges are High, Dreams r New..
The World out thr is waiting for U !!
Dare to dream, Dare to Try..
No Goal is distant, no Star is too high !!!
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shubham_sachdeva (1901)

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OPTIONS CAN ALSO BE WRONG
 
UR QNS. ANS. WAS GIVEN IN FUNDA OF 0 INTERCEPT
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