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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Mar 2007 14:21:00 IST
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WHAT IS THE LOCUS OF THE POINT (1+1/t,1-1/t) WHERE t IS A VARIABLE
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ARUN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Mar 2007 14:30:15 IST
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hi friend take x=1+1/t x-1=1/t-------------(1) y=1-1/t 1-y=1/t-------------(2) equate 1 and 2 1-y=x-1 2=x+y hence the ans bye plzzz rate me
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Mar 2007 16:07:15 IST
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the method is seems to be correct but ans is x^2-y^2=4
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ARUN
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Mar 2007 17:29:14 IST
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i have the same problem
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Mar 2007 18:37:12 IST
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x^2-y^2=4 cant be answer.... cuz on putting the values of x and y, as given, u'll get this result only for a particular value of t and not for any variable t... so this cant be the answer.. wat aman has solved is the rite one!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Mar 2007 20:31:58 IST
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Dear arun, wht magiclko has written is write. locus of the point will be the curve which contains all points that comes for all possible values of t. so eq of locus must satisfies all such points but if you observe by putting your point on curve you will find that it will satisfies for only t=1 so please check the ans. once again. if doubt any please ask.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Mar 2007 11:52:20 IST
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yeS THAT WOULD BE CORRECT
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ARUN
TRY,TRY,TRY TILL U SUCCEEEEEEEEEEEEEEEEEEED
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