I dont think thats possible, try it out like this.
In a triangle ABC, lets suppose B is obtuse, say 2pi/3. Let sides of the triangle be a=m, b=mr, and c=mr2. Now, apply cosine rule,
cos(2pi/3) =a2+c2-b2/2ac
-1/2 = m2 + m2r4 - m2r2/2m2r2
-1/2*2r2 = r4 -r2+1
which gives,
r4= -1
which is not possible, so i dont think there might be any triangle of that sort.