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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 May 2008 12:41:04 IST
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pls help:da eq of da circle cicumcribing da triangle formed by da lines x+y=6,2x+y=4,x+2y=5
options r
a)x^2+y^2-15x-16y+50=0
b)x^2+y^2+15x+16y+50=0
c)x^2+y^2-17x-19y+50=0
d)x^2+y^2+17x+19y+50=0
(pls mention if dere is any shortcut method to it
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1 May 2008 12:49:30 IST
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plsssssssss reply
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DONT AIM FOR PERFECTION JUST ACHIEVE IT |
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The points of intersection of the three lines are (-7,8) (1,2) and (7,-1)...these points should satisfy one of the options....that would be the answer...!!!
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