IIT JEE , AIEEE Forum - Mathematics , Analytical Geometry

kushi12

find the equation to the circles in which the line joining the points (a,b) and (b,-a)is a chord subtending an angle of 45deg at any point on circumference

sachinguptaiit

Let the centre be (h,k)

Now it subtends angle of $eq=90^{\circ}$ at the centre of the circle

hence we can say

$eq=\frac{k-b}{h-a}.\frac{k+a}{h-b}=-1$

Hence equation of circle is

$eq=(x-a)(x-b)+(y+a)(y-b)=0$

jishnudas1991

Re:pls solve

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