vertex is mid pt of focus n directrix meeting pt of drtx =(m,n) 1=(m-2)/2 m=4 similarly n=1 slope if axis =-1/3 thus slope of drtx=3(perpendicular to axis ) now eqn to drtx=3=(y-1)/(x-4) frm dis eqn den put distanc frm dirtx=distance frm focus (3x-y-11)^2/10=(x+2)^2(y-3)^2 hence d eqn
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