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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Apr 2008 21:49:07 IST
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(-7,6,-3) and (7,-6,3).
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 07:51:41 IST
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u can use the two point form for dis.. that is..y-y1=m(x-x1) where m is the slope of the line and m=y2-y1/(x2-x1)..hope u got it..!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 07:52:33 IST
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hey but what about the z coordinates..??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Apr 2008 08:05:04 IST
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ooh am sorry..didn't notice the z coordinates... in this case u can use the form x-x1/x2-x1 = y-y1/y2-y1 = z-z1/z2-z1..rite?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Apr 2008 16:18:52 IST
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The direction ratios of the line are (14,-12,6) or (7,-6,3)
So,the eqn of the line is x-7/7=y+6/-6=z-3/3.we can take any point & substitute(I took the 2nd one)
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