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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2007 11:09:33 IST
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Range of m...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2007 15:30:11 IST
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The tangent to ellipse is y=mx+root((am)^2+b^2)
The tangent to parabola is y=mx+a/m
Since common tangent is required both the equations are same.
So (am)^2+b^2=(a/m)^2
or b=a*root(1-m^4)/m
For b to be defined 0<m<1 and -1<m<0
Also m cannot be zero.
So b) is the answer.
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ADARSH
NITK Surathkal
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this reply: 10 points
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 17:40:52 IST
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thnx man...rated u...
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