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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:05:08 IST
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Solve the following problems based on coordinate geometry and help me please.? i) what is the area of the triangle whose vertices are (-3,3) , (-1,-4), and (5,-2)
what is the area of the triangle whose vertices are (3,-4), (1,6), (-2,3)
ii) (2,x), (4,6), and (-8,8) are collinear, find out the value of x.
iii) vertices of a triangle are (3,-4), (1,6), (-2,3)
find the circumcentre and the circumradius of the triangle whose vertices are (3,-4), (1,6), (-2,3)
i will be extreamly grateful if u solve these problems.please
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KRITHIKA |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:08:52 IST
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answer1) representing those points in the determinant form,
I -3 3 1I I -1 -4 1I = 46... I 5 -2 1I So area of triangle = 1/2*46 = 23... similarly, using determinant form,area of the triangle formed by,(3,-4),(1,6),(-2,3) = 1/2*36 = 18........
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:15:19 IST
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answer2)as the 3 points r collinear, the area of the triangle formed by those points = 0............... therefore 1/2* I 2 x 1I I 4 6 1I = 0............ I-8 8 1I hence,
12x = 76 x = 19/3 = 6.3
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:31:09 IST
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let A=(-3,4);B = (1,6);C = (-2,3).......... we know that circumcentre is the pt of intersection of the perpendicular bisectors......... let,D be the midpoint of side BC............ so, D = (-1/2,9/2) now slope of the perpendicular bisector*slope of BC = -1.................... so get the equation of the P.B.......... similarly take another side n its midpt. find tht P.B. intersection of these 2 P.B.'s is the circumcentre...................
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:34:12 IST
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circumradius is the distance between A or B or C and the circumcentre ..........!!!!!!!!!!!
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Aug 2007 14:35:13 IST
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solve it further n u will get the required answer............!!!!!!!!!!!!!!!!!!!!!!!!
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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Please ask one question at a time.
Area of triangle formed by vertices (x1,y1) ; (x2,y2) ; (x3,y3) is given by :
A = (1/2).| x1(y2-y3) + x2(y3-y1) + x3(y1-y2) |
Now put the values and get the answer.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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