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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: straight lines
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ishan.maheshwari (161)

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specify the method to solve the below given question.( as i know the answer but not the correct method to solve it ) :
find the equation of the straight line on which the length of the perpendicular from the origin is 2 and the perpendicular makes an angle   with the x axis such that sin  = 1 / 3     (answer : 2 2x+y = 6  )

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catch_arnnie (521)

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solution:
let the equation of the line be y=mx+c,
 

since,  sin =1/3 , therefore, tan  = 1/22
=> m= -22(since the lines are perpendicular)
 
the equation now becomes y + 22x - c = 0
 
the line is at a distance of 2 units from the origin, so
using the "perpendicular distance of a point from a line" formula,
we get, | -c/3 | = 2
=>c=6
 
therefore, the final equation is y + 22x = 6
 
ask me if you didn't understand the solution.....

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ishan.maheshwari (161)

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i did not understand what u did. can u please explain

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vinu (524)

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simple......use normal form of eq...
 
xcos@ + ysin@ = p ; (whr p = perp dist from origin ; tan@ = slope) ;
 
x (2 2 / 3) + y/3 = 2 ; 22 x +y = 6 .
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shivamk (51)

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Its very simple. Once again use the normal form of equation of a line.Ihave given the detailed explaination of normal form in your previous post.  Now the normal form of equation of a ine is given by xcos+ysin.Hence cos=2[ ]2/8 . Hence v get the final equation of  the line.
 
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